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Train P going at a speed of 72 km/hr completely passes train Q of length 393 m, going in the same direction on parallel tracks at 42 km/hr, in 1.5 min
Question

Train P going at a speed of 72 km/hr completely passes train Q of length 393 m, going in the same direction on parallel tracks at 42 km/hr, in 1.5 minutes. How much time (in seconds) will train P take to completely cross train R of length 468 m, going at 63 km/hr in the opposite direction?

A.

32

B.

24

C.

22

D.

10

Correct option is C

Given:
Speed of Train P = 72 km/hr
Speed of Train Q = 42 km/hr
Length of Train Q = 393 m
Time taken to cross Q = 1.5 minutes = 90 seconds
Speed of Train R = 63 km/hr
Length of Train R = 468 m
Formula Used:
Relative Speed (Same Direction) = S1S2 S_1 - S_2​​
Relative Speed (Opposite Direction) = S1+S2S_1 + S_2​​
Distance = Speed × Time
Solution:
Relative speed of P with respect to Q (same direction):
= 72 - 42 = 30 km/hr
Convert to m/s: 30×518=253 m/s30 × \frac{5}{18} = \frac{25}{3} \text{ m/s}​​
Total distance covered to cross train Q = Length of P + Length of Q = LP+393 L_P + 393​​
Distance = Speed × Time
LP+393=253×90L_P + 393 = \frac{25}{3} × 90​​

LP+393=750L_P + 393 = 750​​

LPL_P​ = 750 - 393 = 357 m
Now, calculate for train P crossing train R (opposite direction):
Relative speed = 72 + 63 = 135 km/hr
Convert to m/s: 135×518=752 m/s 135 × \frac{5}{18} = \frac{75}{2} \text{ m/s}​​
Total distance to cross train R  = 357 + 468 = 825 m
Time = 825752=825×275\frac{825}{\frac{75}{2}} = \frac{825 × 2}{75}​​
= 11 × 2 = 22 seconds
Final Answer
So the correct answer is (c)

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