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    If a=101,b=102 and c=103, then a2+b2+c2-ab-bc-ca=
    Question

    If a=101,b=102 and c=103, then a2+b2+c2-ab-bc-ca=

    A.

    2

    B.

    4

    C.

    3

    D.

    6

    Correct option is C

    Given: 
    a = 101 , b = 102, c = 103 
    Expression: a2+b2+c2-ab-bc-ca 
    Formula Used: 
    ​a3+b3+c3−3abc=12(a+b+c)[(a−b)2+(b−c)2+(c−a)2]a^3+b^3 + c^3 -3abc = \frac{1}{2}(a+b+c)[(a-b)^2+(b-c)^2+(c-a)^2] 
    Solution:
    ​

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