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If a=101,b=102 and c=103, then a2+b2+c2-ab-bc-ca=
Question

If a=101,b=102 and c=103, then a2+b2+c2-ab-bc-ca=

A.

2

B.

4

C.

3

D.

6

Correct option is C

Given: 
a = 101 , b = 102, c = 103 
Expression: a2+b2+c2-ab-bc-ca 
Formula Used: 
a3+b3+c33abc=12(a+b+c)[(ab)2+(bc)2+(ca)2]a^3+b^3 + c^3 -3abc = \frac{1}{2}(a+b+c)[(a-b)^2+(b-c)^2+(c-a)^2] 
Solution:

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