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    If 5x + 4y = 12 and xy = 2, then find the value of 125x³ + 64y³.
    Question

    If 5x + 4y = 12 and xy = 2, then find the value of 125x³ + 64y³.

    A.

    288

    B.

    286

    C.

    268

    D.

    258

    Correct option is A

    Given:

    5x + 4y = 12

    xy = 2

    Formula Used:

    (a+b)2=a3+b3+3ab(a+b) (a+b)^2 = a^{3} + b^{3} +3ab (a+ b)​​

    Solution:  

    Using the formula:

    (5x+4y)3=125x3+64y3+3(5x)(4y)[5x+4y] (12)3=125x3+64y3+60(2)[12] 1728=125x3+64y3+1440 125x3+64y3=17281440=288(5x+4y)^3 = 125x^3 +64y^3 +3(5x)(4y)[5x+4y] \\ \ \\ (12)^3 = 125x^3 +64y^3+60(2)[12] \\ \ \\ 1728= 125x^3 +64y^3 +1440 \\ \ \\ 125x^3 +64y^3 = 1728 - 1440 = 288​​

    The value of 125x3+64y3125x^3 + 64y^3​ is 288

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