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If 5x + 4y = 12 and xy = 2, then find the value of 125x³ + 64y³.
Question

If 5x + 4y = 12 and xy = 2, then find the value of 125x³ + 64y³.

A.

288

B.

286

C.

268

D.

258

Correct option is A

Given:

5x + 4y = 12

xy = 2

Formula Used:

(a+b)2=a3+b3+3ab(a+b) (a+b)^2 = a^{3} + b^{3} +3ab (a+ b)​​

Solution:  

Using the formula:

(5x+4y)3=125x3+64y3+3(5x)(4y)[5x+4y] (12)3=125x3+64y3+60(2)[12] 1728=125x3+64y3+1440 125x3+64y3=17281440=288(5x+4y)^3 = 125x^3 +64y^3 +3(5x)(4y)[5x+4y] \\ \ \\ (12)^3 = 125x^3 +64y^3+60(2)[12] \\ \ \\ 1728= 125x^3 +64y^3 +1440 \\ \ \\ 125x^3 +64y^3 = 1728 - 1440 = 288​​

The value of 125x3+64y3125x^3 + 64y^3​ is 288

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