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If 3cot⁡θ=tan⁡θ then the principal value of θ is\text{If } 3 \cot \theta = \tan \theta \text{ then the princip
Question

If 3cotθ=tanθ then the principal value of θ is\text{If } 3 \cot \theta = \tan \theta \text{ then the principal value of } \theta \text{ is}​​​

A.

π3\frac{π}{3}​​

B.

π2\frac{π}{2}​​

C.

π6\frac{π}{6}​​

D.

π4\frac{π}{4}​​

Correct option is A

Given:

3cotθ=tanθ3\cot\theta=\tan\theta 

Solution:

3cotθ=tanθ3\cot\theta=\tan\theta 

3cosθsinθ=sinθcosθ3\frac{\cos\theta}{\sin\theta}=\frac{\sin\theta}{\cos\theta} 

3cos2θ=sin2θ3\cos^2\theta= sin^2\theta        (sin2θ=1cos2θ\sin^2\theta= 1- \cos^2\theta)

3cos2θ=1cos2θ3\cos^2\theta= 1-\cos^2\theta

3cos2θ+cos2θ=13\cos^2\theta+\cos^2\theta= 1 

4cos2θ=14\cos^2\theta= 1 

cos2θ=14\cos^2\theta= \frac14

cosθ=12\cos\theta= \frac12 

cosθ=cos60\cos\theta= \cos60^\circ 

θ=60\theta= 60^\circ  =     60=π360^\circ= \frac{\pi}{3} 

Because π\pi= 180

Option (a)

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