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    If 3cot⁡θ=tan⁡θ then the principal value of θ is\text{If } 3 \cot \theta = \tan \theta \text{ then the princip
    Question

    If 3cotθ=tanθ then the principal value of θ is\text{If } 3 \cot \theta = \tan \theta \text{ then the principal value of } \theta \text{ is}​​​

    A.

    π3\frac{π}{3}​​

    B.

    π2\frac{π}{2}​​

    C.

    π6\frac{π}{6}​​

    D.

    π4\frac{π}{4}​​

    Correct option is A

    Given:

    3cotθ=tanθ3\cot\theta=\tan\theta 

    Solution:

    3cotθ=tanθ3\cot\theta=\tan\theta 

    3cosθsinθ=sinθcosθ3\frac{\cos\theta}{\sin\theta}=\frac{\sin\theta}{\cos\theta} 

    3cos2θ=sin2θ3\cos^2\theta= sin^2\theta        (sin2θ=1cos2θ\sin^2\theta= 1- \cos^2\theta)

    3cos2θ=1cos2θ3\cos^2\theta= 1-\cos^2\theta

    3cos2θ+cos2θ=13\cos^2\theta+\cos^2\theta= 1 

    4cos2θ=14\cos^2\theta= 1 

    cos2θ=14\cos^2\theta= \frac14

    cosθ=12\cos\theta= \frac12 

    cosθ=cos60\cos\theta= \cos60^\circ 

    θ=60\theta= 60^\circ  =     60=π360^\circ= \frac{\pi}{3} 

    Because π\pi= 180

    Option (a)

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