Correct option is CGiven: 2a + 3b = 10 ab = 3 To find: 4a2+9b24a^2+9b^24a2+9b2 Formula Used: (a+b)2=a2+b2+2⋅a⋅b(a+b)^2 = a^2 + b^2 + 2\cdot a \cdot b(a+b)2=a2+b2+2⋅a⋅bSolution: Squaring 2a + 3b = 10 (2a+3b)2=(10)24a2+9b2+2×2a×3b=1004a2+9b2=100−12ab4a2+9b2=100−12×34a2+9b2=100−364a2+9b2=64(2a+3b)^2 = (10)^2 \\ 4a^2 + 9b^2 +2 \times 2a \times3b = 100 \\ 4a^2 + 9b^2 = 100 - 12a b \\ 4a^2 +9b^2 = 100 - 12 \times 3 \\ 4a^2 + 9 b^2 = 100 - 36 \\ 4a^2 + 9b^2 =\bf 64(2a+3b)2=(10)24a2+9b2+2×2a×3b=1004a2+9b2=100−12ab4a2+9b2=100−12×34a2+9b2=100−364a2+9b2=64