If √2 sin (5x -5)° =tan 45°, then the value of (in degrees) is:

Correct option is C

Given:

​√2 sin (5x -5)° =tan 45°

Formula Used:

​$$\tan 45^\circ = 1\\\sin 45^\circ = \frac{1}{\sqrt{2}}$$ 

Solution:

​√2 sin (5x -5)° =tan 45°

​√2 sin (5x -5)° =1

​sin (5x -5)° =1/​√2

​sin (5x -5)° = sin⁡45

5x =50$$\degree$$​​

So, value of x=10$$\degree$$​​
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