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If (2, –2) and (5, 2) are two consecutive vertices of a square, then the length of each side of the square will be:
Question

If (2, –2) and (5, 2) are two consecutive vertices of a square, then the length of each side of the square will be:

A.

5 units

B.

525\sqrt{2} units​

C.

52\tfrac {5}{\sqrt2} units​

D.

5\sqrt{5} units​

Correct option is A

Given:

Two consecutive vertices of a square: (2,−2) and (5,2)

Formula Used:

The distance between two points (x1,y1) and (x2,y2) is:

Distance=(x2x1)2+(y2y1)2\text{Distance} = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}​​

For a square, the distance between two consecutive vertices is equal to the side length.

Solution:

Apply the distance formula:

Side length=(52)2+(2(2))2\text{Side length} = \sqrt{(5 - 2)^2 + (2 - (-2))^2}

Side length =(3)2+(4)2\sqrt{(3)^2 + (4)^2}​​

Side length=9+16=25=5\text{Side length} = \sqrt{9 + 16} = \sqrt{25} = 5

Option (a) is right.

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