If 1x2+a2=x2−a2\frac{1}{x^2+a^2}=x^2-a^2x2+a21=x2−a2, then the value of x is:
If x + 1x\frac 1xx1= –1, then compute: x4+1x4+2x2+2x2x^4 + \frac{1}{x^4} + 2x^2 + \frac{2}{x^2}x4+x41+2x2+x22
Simplify: 4(74x2−27x+19)−7(x2+9x−14)\text{Simplify: } 4\left(\frac{7}{4}x^2 - 27x + 19\right) - 7(x^2 + 9x - 14)Simplify: 4(47x2−27x+19)−7(x2+9x−14)
If x−1x=3, then the value of x4+1x4 is:\text{If } x - \frac{1}{x} = 3, \text{ then the value of } x^4 + \frac{1}{x^4} \text{ is:}If x−x1=3, then the value of x4+x41 is:
Simplify8x3+27y3−64z3+72xyz4x2+9y2+16z2−6xy+12yz+8zx\text{Simplify} \\\frac{8x^3 + 27y^3 - 64z^3 + 72xyz}{4x^2 + 9y^2 + 16z^2 - 6xy + 12yz + 8zx}Simplify4x2+9y2+16z2−6xy+12yz+8zx8x3+27y3−64z3+72xyz
If x−1x=4x - \frac{1}{x} = 4x−x1=4, then the value of x3−1x3x^3 - \frac{1}{x^3}x3−x31 is:
If x−1x=10x - \frac{1}{x} = 10x−x1=10, then the value of x3−1x3x^3 - \frac{1}{x^3}x3−x31 is:
Simplify the following.(2x +3)² − (x + 1)².
If a2+b2=90a^2+b^2 = 90a2+b2=90 and ab = 27, then find the possible value of a+ba−b.\frac{a+b}{a-b}.a−ba+b.
If x+1x=17 then x2+1x2 is:\text{If }x + \frac{ 1}{x} = 17 \text{ then }x^2 + \frac{ 1}{x^2} \text{ is:}If x+x1=17 then x2+x21 is:
If a + b = 41, and a − b = 38, find the value of (a + b)².
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