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If 1x2+a2=x2−a2\frac{1}{x^2+a^2}=x^2-a^2x2+a21​=x2−a2, then the value of x is:​
Question

If 1x2+a2=x2a2\frac{1}{x^2+a^2}=x^2-a^2, then the value of x is:​

A.


B.


C.


D.

Correct option is D

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