If 1234567y is divisible by 11, then what is the value of y?

Correct option is C

Given:
1234567y , is divisible by 11
Concept Used:
Rule for Divisibility by 11-
Subtract the sum of the digits in the odd positions from the sum of the digits in the even positions. If the result is divisible by 11 (including 0), then the original number is divisible by 11.
Solution:
1234567y → 1+3+5+7 – (2+4+6+y) = 16 – 12 – y = 4 – y = 4 -4 = 0
In place of y if we put 4 than we get 0 which satisfy the condition of divisibility rule by 11