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    If 0 stands for the operation "Subtract and double the value", that is a0b = 2(a-b); and Ø stands for "Multiply and halve", that is aØb =12\frac{1}{2}
    Question

    If 0 stands for the operation "Subtract and double the value", that is a0b = 2(a-b); and Ø stands for "Multiply and halve", that is aØb =12\frac{1}{2}​ ab then, find the value of:
    (8Ø6)0(6Ø4)

    A.

    24

    B.

    48

    C.

    36

    D.

    12

    Correct option is A

    Given:

    If 0 stands for the operation "Subtract and double the value", that is a0b = 2(a-b);

    and Ø stands for "Multiply and halve", that is aØb = 12\frac{1}{2} ab

    Solution:

    Calculate (8ϕ\phi6)

    The operation ϕ\phi stands for "Multiply and halve."

    ​8ϕ\phi​6 = 12\frac{1}2 ×(8×6)\times (8\times6) = 12×48\frac{1}{2} \times48 = 24

    ​Calculate  6ϕ46\phi4

    Again, using the operation ϕ\phi

    6ϕ46\phi4 = 12×(6×4)\frac{1}2 \times(6 \times 4) = 12×24\frac{1}2 \times 24 = 12

    ​Calculate the result of (8ϕ\phi​6 )0(​6ϕ46\phi4)

    The operation 0 stands for "Subtract and double."

    (8ϕ6)(8\phi6)​0(​6ϕ46\phi4​) = 2×(24−12) = 2×12 = 24

    Therefore, the value of (8ϕ6)(8\phi6)​​0(​6ϕ46\phi4​) is;

    24

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