Three chocolate bars weighing 600 grams, 420 grams and 780 grams were cut into small pieces of uniform weight. If 2 such bars are given to one person, then what will be the minimum number of such persons between whom all the bars can be distributed?

Correct option is C

Given
Weights: 600g, 420g, 780g

Solution
To have uniform weight pieces, we find the HCF of 600, 420, 780.
HCF = 60g (Largest common divisor)
Total weight = 600 + 420 + 780 = 1800g
Number of pieces = $$\frac{1800}{60}$$​ = 30 pieces.
Each person gets 2 pieces.
Number of persons = $$\frac{30}{2} = 15$$​​

Final Answer
So the correct answer is (c)