Correct option is D
Given
Target Year = 2001
Formula Used
A calendar repeats if the sum of odd days between the years is divisible by 7 (i.e., 0 odd days).
Solution
We need to find a year prior to 2001 with the same calendar.
Let's count odd days backwards from 2000.
2000 (Leap Year) = 2 odd days
1999 (Ordinary Year) = 1 odd day
1998 (Ordinary Year) = 1 odd day
1997 (Ordinary Year) = 1 odd day
1996 (Leap Year) = 2 odd days
1995 (Ordinary Year) = 1 odd day
1994 (Ordinary Year) = 1 odd day
1993 (Ordinary Year) = 1 odd day
1992 (Leap Year) = 2 odd days
1991 (Ordinary Year) = 1 odd day
1990 (Ordinary Year) = 1 odd day
Sum of odd days = 2 + 1 + 1 + 1 + 2 + 1 + 1 + 1 + 2 + 1 + 1 = 14
Since 14 is divisible by 7, the calendar of 1990 is the same as that of 2001.
Final Answer
So the correct answer is (d)