Correct option is A
- The first gate is an OR gate.
- Input A enters directly.
- Input B first passes through a NOT gate, producing B′.
Therefore, the output of the first gate is:
[A + B']
Step 2: Inversion of Input C
- Input C passes through a NOT gate.
Hence,
[C']
Step 3: Second Logic Gate (AND Gate)
- The output ((A + B')) and (C') are applied to an AND gate.
Output becomes:
Step 4: Final Logic Gate (OR Gate)
- The output from the AND gate is ORed with input D.
Thus, the final output expression is:
[(A + B')C' + D]
Final Boolean Expression
