Correct option is A
Let's break down the circuit from the image:
1. Inputs: The circuit has four inputs: A, B, C, and D.
2. Logic Gates:
· The first gate is a NAND gate with inputs A and B. The output of this gate will be: (A · B)'.
· The second gate is a NOT gate applied to input C. The output will be: C'.
· The third gate is another NOT gate applied to input B, giving: B'.
· The final logic operation involves an OR gate that takes three inputs:
· The output from the first NAND gate: (A · B)'
· The output from the second NOT gate: C'
· The input D.
Boolean Expression:
· The NAND gate with inputs A and B gives (A · B)'.
· The NOT gate on C gives C'.
· The OR gate combines:
· (A · B)'
· C'
· D
The resulting Boolean expression is: (A · B)' + C' + D
