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    In Boolean algebra, A·(A + B) is logically equivalent to:
    Question

    In Boolean algebra, A·(A + B) is logically equivalent to:

    A.

    B

    B.

    A·B

    C.

    A + B

    D.

    A

    Correct option is D

    In Boolean algebra, the expression A · (A + B) simplifies to A based on the Distributive Law and Idempotent Law.
    Simplification Steps:
    1. Distributive LawA(A+B)=(AA)+(AB)A \cdot (A + B) = (A \cdot A) + (A \cdot B)​​
    2. Idempotent LawAA=AA \cdot A = A​ So, the expression becomes:
    A+(AB)A + (A \cdot B)​​
    3. Absorption LawA+(AB)=AA + (A \cdot B) = A​ This is because A absorbs A · B. If A is true, the entire expression is true, regardless of B.
    Thus, the expression simplifies to A.
    Important Key Points:
    1. Distributive LawA(A+B)=AA+ABA \cdot (A + B) = A \cdot A + A \cdot B​​
    2. Idempotent LawAA=AA \cdot A = A​​
    3. Absorption LawA+(AB)=AA + (A \cdot B) = A​​
    Knowledge Booster:
    · Option (a): B is incorrect. The simplified expression is A, not B.
    · Option (b): A · B is incorrect because we don't end up with a product of A and B in this simplification.
    · Option (c): A + B is incorrect because the result of the simplification is A, not A + B.

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