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In Boolean algebra, A·(A + B) is logically equivalent to:
Question

In Boolean algebra, A·(A + B) is logically equivalent to:

A.

B

B.

A·B

C.

A + B

D.

A

Correct option is D

In Boolean algebra, the expression A · (A + B) simplifies to A based on the Distributive Law and Idempotent Law.
Simplification Steps:
1. Distributive LawA(A+B)=(AA)+(AB)A \cdot (A + B) = (A \cdot A) + (A \cdot B)​​
2. Idempotent LawAA=AA \cdot A = A​ So, the expression becomes:
A+(AB)A + (A \cdot B)​​
3. Absorption LawA+(AB)=AA + (A \cdot B) = A​ This is because A absorbs A · B. If A is true, the entire expression is true, regardless of B.
Thus, the expression simplifies to A.
Important Key Points:
1. Distributive LawA(A+B)=AA+ABA \cdot (A + B) = A \cdot A + A \cdot B​​
2. Idempotent LawAA=AA \cdot A = A​​
3. Absorption LawA+(AB)=AA + (A \cdot B) = A​​
Knowledge Booster:
· Option (a): B is incorrect. The simplified expression is A, not B.
· Option (b): A · B is incorrect because we don't end up with a product of A and B in this simplification.
· Option (c): A + B is incorrect because the result of the simplification is A, not A + B.

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