Correct option is A
Given:
To find: how many numbers from 1 to 430 are divisible by both 7 and 11.
Concept Used:
If a number is divisible by both 7 and 11, it is divisible by their least common multiple (LCM). The LCM of 7 and 11 is:
LCM(7,11) = 7 × 11 = 77
Solution:
The numbers divisible by 77 are of the form 77 × k, where k is an integer.
Finding the largest integer k such that 77× k ≤ 430:
k=⌊77430⌋=⌊5.58⌋=5
The numbers divisible by 77 from 1 to 430 are:
77 × 1 = 77 , 77 × 2 = 154,77 × 3 = 231, 77 × 4 = 308, 77 × 5 = 385
Thus, There are 5 numbers between 1 and 430 that are divisible by both 7 and 11.