Question


A.

2 cos 2θ

B.

cos 3θ

C.

2 cos 3θ

D.

cos 2θ

Correct option is C

Given:

x + 1x\frac{1}{x}​ = 2 cos θ

Formula Used:

4cos3θ3cosθ=cos3θ4 cos^3 θ - 3 cos θ = cos 3θ​​

Solution:

x3+1x3=8cos3θ6cosθ =2[4cos3θ3cosθ] =2(cos3θ) =2cos3θx^3 + \frac{1}{x^3} = 8 cos^3 θ - 6 cos θ\\\ \\= 2 [4 cos^3 θ - 3 cos θ]\\\ \\= 2 (cos 3θ)\\\ \\= 2 cos 3θ​​

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