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    Question


    A.

    1

    B.

    –1

    C.

    0

    D.

    –2

    Correct option is A

    Given:

    x+1x=1x + \frac{1}{x} = 1 ​​

    Formula Used:  

    a3+b3=(a+b)(a2+b2ab)a^3 + b^3 = (a+b)(a^2 +b^2 - ab) 

    Solution:

    x+1x=1​x + \frac{1}{x} = 1   

    x2x+1=0x^2 - x + 1 = 0​​

    x3+13=(x+1)(x2x+1)=0x^3 + 1^3 = (x + 1)(x^2 - x + 1) = 0​​

    x3=1x^3 = -1

    Then the value x12+x9+x6+x3+1x^{12}+x^9 +x^6 +x^3 +1​​

    Thus,  x9(x3+1)+x3(x3+1)+1=1x^9 (x^3 + 1) + x^3 (x^3 + 1) + 1 = 1​​

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