Solution:
Let ab be a two digit number.
So, we can write ab = 10a + b
Now, sum of digits of Two - digit number ab is a+b
⇒ 10a+b-(a+b) = 10a+b-a-b = 9a
Hence, Clearly we can see 9a is always divisible by 9
Hence, Option (b) is true
Find the Highest Common Factor (HCF) of 372, 732 and 2196.
What is the year before 2001 whose calendar is the same as 2001?
Find the fraction of 0.538888...
Let A and B be two sets such that n(A – B) = 20 + x, n(B – A) = 3x and n(A∩B) = x + 1. If n(A) = n(B), then the value of (2x – 5) is:
Let p be the greatest number of 4-digits which when divided by 21, 22, 24 and 28, the remainder in each case is 8. What is the sum of the digits of p?
