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From a point 30 m away from the base of a tree, the angle of elevation of the top of the tree is 60°. Find the height of the tree (take √3 = 1.73).
Question

From a point 30 m away from the base of a tree, the angle of elevation of the top of the tree is 60°. Find the height of the tree (take √3 = 1.73).

A.

52.5 m

B.

51.9 m

C.

54 m

D.

51 m

Correct option is B

Given:
Distance from the base of the tree = 30 m
Angle of elevation = 60°
Formula Used:
tan(θ)=HeightBase\tan(\theta) = \frac{Height}{Base}​​
Solution: 

Let the height of the tree be H.
tan(60°)=H30\tan(60°) = \frac{H}{30}​​
We know that  tan(60°)=3.\tan(60°) = \sqrt{3}.​​
3=H30\sqrt{3} = \frac{H}{30}​​
H =  30×330 × \sqrt{3}​​
H = 30 × 1.73
H = 51.9
The height of the tree is 51.9 m.
Final Answer
So the correct answer is (b)

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