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A building casts a shadow of length 46 m, when the angle of elevation of the sun is 600.60^0.600.​ Find the height of the building. (Use √3 = 1.7
Question

A building casts a shadow of length 46 m, when the angle of elevation of the sun is 600.60^0.​ Find the height of the building. (Use √3 = 1.7)

A.

82.4 m

B.

66.4 m

C.

56.2 m

D.

78.2 m

Correct option is D

Given
Length of shadow = 46 m
Angle of elevation = 6060^{\circ}​​
3=1.7\sqrt{3} = 1.7​​
Formula Used
tan(θ)=PerpendicularBase\tan(\theta) = \frac{\text{Perpendicular}}{\text{Base}}​​
Solution
tan(60)=Height46 3=Height46 1.7=Height46 \tan(60^{\circ}) = \frac{\text{Height}}{46} \\\ \\\sqrt{3} = \frac{\text{Height}}{46}\\\ \\1.7 = \frac{\text{Height}}{46}\\\ \\​​
Height = 46×1.7=78.246 \times 1.7 = 78.2​ m
Final Answer
So the correct answer is (d)

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