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For the following equations, what are the values of a and b to have infinitely many solutions? ax + by = 23x - (5 - 2a)y = 6
Question

For the following equations, what are the values of a and b to have infinitely many solutions?
ax + by = 2
3x - (5 - 2a)y = 6

A.

a = -1, b = 1

B.

a = -1, b = -1

C.

a = 1, b = -1

D.

a = 1, b = 1

Correct option is C

Solution:

ax + by = 2

3x - (5 - 2a)y = 6

To find the values of a and b that make the system of equations have infinitely many solutions, we use the condition that two equations must be proportional to each other.

The proportionality condition is:

a3=b(52a)=26\frac{a}{3} = \frac{b}{-(5 - 2a)} = \frac{2}{6}​​

From the third part of the ratio, 26=13\frac{2}{6 }= \frac{1}{3}​, so we have:

a3=13\frac{a}{3}= \frac{1}{3}​ (equating the first part of the ratio),

This gives a = 1.

Substitute a = 1 into the second ratio:

b(52a)=13\frac{b}{-(5 - 2a) }= \frac{1}{3}​​

Substituting a = 1:

b3=13\frac{b}{-3} = \frac{1}{3}​​

Solving for b gives: b = -1

Therefore, the values of a and b that make the system have infinitely many solutions are a = 1 and b = -1.

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