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For a Poisson distribution model, if the arrival rate of passengers at an airport is recorded as 30 per hour, the probability of exactly 4 arrivals in
Question

For a Poisson distribution model, if the arrival rate of passengers at an airport is recorded as 30 per hour, the probability of exactly 4 arrivals in the first 10 minutes of an hour is:

A.

​304⋅e−304!\frac{30^4 \cdot e^{-30}}{4!} \\​​

B.

​54⋅e−54!\frac{5^4 \cdot e^{-5}}{4!} \\​​

C.

​44⋅e−44!\frac{4^4 \cdot e^{-4}}{4!} \\​​

D.

​45⋅e−54!\frac{4^5 \cdot e^{-5}}{4!} \\​​

Correct option is B

Given:
λ=30\lambda = 30​ per hour
Time interval = 10 minute  = =16= \frac{1}{6} ​ hour
​=>λ′=30×16=5k=4\Rightarrow \lambda' = 30 \times \frac{1}{6} = 5 \\k = 4 \\​​
Formula used:
​P(X=k)=λ′k⋅e−λ′k!P(X = k) = \frac{\lambda'^k \cdot e^{-\lambda'}}{k!} \\​​
Solution:
​P(X=4)=54⋅e−54!P(X = 4) = \frac{5^4 \cdot e^{-5}}{4!}​​
Correct answer is (b)

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