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    Question

    find the value of

    A.

    2702

    B.

    2704

    C.

    4096

    D.

    2706

    Correct option is A

    Given: 

    y+1y=4 Value of    y2+1y2y+\frac{1}{y}=4 \\ \text{ Value of }\ \ \ y^2+\frac{1}{y^2} 

    Formula Used: 

    (y+1y)2=y2+(1y)2+2\left(y+ \frac{1}{y} \right)^2 = y^2 + \left(\frac{1}{y} \right)^2 + 2    

    Solution:

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