Correct option is AGiven: y+1y=4 Value of y2+1y2y+\frac{1}{y}=4 \\ \text{ Value of }\ \ \ y^2+\frac{1}{y^2}y+y1=4 Value of y2+y21 Formula Used: (y+1y)2=y2+(1y)2+2\left(y+ \frac{1}{y} \right)^2 = y^2 + \left(\frac{1}{y} \right)^2 + 2 (y+y1)2=y2+(y1)2+2 Solution: