Question

find the value of

A.

2702

B.

2704

C.

4096

D.

2706

Correct option is A

Given: 

y+1y=4 Value of    y2+1y2y+\frac{1}{y}=4 \\ \text{ Value of }\ \ \ y^2+\frac{1}{y^2} 

Formula Used: 

(y+1y)2=y2+(1y)2+2\left(y+ \frac{1}{y} \right)^2 = y^2 + \left(\frac{1}{y} \right)^2 + 2    

Solution:

Free Tests

Free
Must Attempt

SSC GD PYP (Held on 4 Feb 2025 S1)

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
Free
Must Attempt

Hindi Section Test 1

languageIcon English
  • pdpQsnIcon20 Questions
  • pdpsheetsIcon40 Marks
  • timerIcon12 Mins
languageIcon English
Free
Must Attempt

SSC GD Constable Full Mock Test 1

languageIcon English
  • pdpQsnIcon80 Questions
  • pdpsheetsIcon160 Marks
  • timerIcon60 Mins
languageIcon English
test-prime-package

Access ‘SSC CGL Tier I’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
368k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow