Question

Find the value of

A.


B.


C.


D.


Correct option is C

Given: 

cos2150sin2150cos21450+sin21450\frac{ \cos^2 15^0 - \sin^2 15^0}{\cos^2 145^0 + \sin^2 145^0}   

Formula Used:  

sin2θ+cos2θ=1cos2θ=cos2θsin2θcos300=32\begin{aligned}&\sin^2 \theta + \cos^2 \theta =1 \\&\cos 2 \theta = \cos^2 \theta - \sin^2 \theta \\&\cos 30^0 = \frac{ \sqrt{3}}{2} \end{aligned}    

Solution:

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