Find the value of the expression: 
​$$\frac{(0.12 \times 0.12 \times 0.12) + (0.012 \times 0.012 \times 0.012)}{(0.48 \times 0.48 \times 0.48) + (0.048 \times 0.048 \times 0.048)}$$​​

Correct option is D

Given:
​$$\frac{(0.12 \times 0.12 \times 0.12) + (0.012 \times 0.012 \times 0.012)}{(0.48 \times 0.48 \times 0.48) + (0.048 \times 0.048 \times 0.048)}$$ 
Solution: 
​$$\frac{(0.12 \times 0.12 \times 0.12) + (0.012 \times 0.012 \times 0.012)}{(0.48 \times 0.48 \times 0.48) + (0.048 \times 0.048 \times 0.048)}$$ 

$$=\frac{0.12^3 + 0.012^3}{0.48^3 + 0.048^3}\\\ \\=\frac{12^3[0.1^3 + 0.01^3]}{48^3[0.1^3 + 0.01^3]}\\\ \\=\frac{12^3}{48^3}\\\ \\=\frac{12}{48}^3\\\ \\=\frac{1}{4}^3\\\ \\=\frac{1}{64}$$ 


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