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Find the value of (74+47)2+(74−47)2742+472\frac{(74+47)^2+(74-47)^2}{74^2+47^2}742+472(74+47)2+(74−47)2​​
Question

Find the value of (74+47)2+(7447)2742+472\frac{(74+47)^2+(74-47)^2}{74^2+47^2}

A.

2

B.

47

C.

1

D.

74

Correct option is A

Given:

(74+47)2+(7447)2742+472\frac{(74 + 47)^2 + (74 - 47)^2}{74^2 + 47^2}​​

Formula Used:

(a+b)2+(ab)2=2a2+2b2=2(a2+b2)(a + b)^2 + (a - b)^2 = 2a^2 + 2b^2 = 2(a^2 + b^2)

Solution:
(74+47)2+(7447)2742+472\frac{(74 + 47)^2 + (74 - 47)^2}{74^2 + 47^2}

=2(742+472)742+472=\frac{2(74^2 + 47^2)}{74^2 + 47^2}

= 2

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