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    Find the value of (3+3tan⁡2A)cot⁡A(1+cot⁡2A)sec⁡A\frac{(3 + 3\tan^2 A)\cot A}{(1 + \cot^2 A)\sec A}(1+cot2A)secA(3+3tan2A)cotA​.​
    Question

    Find the value of (3+3tan2A)cotA(1+cot2A)secA\frac{(3 + 3\tan^2 A)\cot A}{(1 + \cot^2 A)\sec A}.​

    A.

    tanA

    B.

    sinA

    C.

    3sinA

    D.

    3tanA

    Correct option is C

    Given: 

    (3+3tan2A)cotA(1+cot2A)secA\frac{(3 + 3\tan^2 A)\cot A}{(1 + \cot^2 A)\sec A} 

    Formula Used: 

    1+tan2A=sec2A 1+cot2A=cosec2A1+\tan^2A = \sec^2 A \\ \ \\ 1 +\cot^2A = \cosec^2A 

    Solution: 

    (3+3tan2A)cotA(1+cot2A)secA =3(1+tan2A)cotAcosec2A×secA =3(sec2A)cotAcosec2A×secA =3(secA)×cosecAsecAcosec2A =3cosecAcosec2A=3sinA\frac{(3 + 3\tan^2 A)\cot A}{(1 + \cot^2 A)\sec A} \\ \ \\ = \frac{3(1 + \tan^2 A)\cot A}{\cosec^2A \times\sec A} \\ \ \\ = \frac{3(\sec^2 A)\cot A}{\cosec^2A \times\sec A}\\ \ \\ = \frac{3(\sec A)\times\frac{\cosec A}{\sec A}}{\cosec^2A }\\ \ \\ = \frac{3\cosec A}{\cosec^2A } = 3\sin A​​

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