Find the value of $$\left( \frac{1}{4} \right)^{-4} + \left( \frac{1}{2} \right)^{-4} + \left( \frac{1}{6} \right)^{-4}$$​​

Correct option is A

Given:
​$$\left( \frac{1}{4} \right)^{-4} + \left( \frac{1}{2} \right)^{-4} + \left( \frac{1}{6} \right)^{-4} \\$$ 
Formula Used:
​$$\left( \frac{1}{a} \right)^{-n} = a^n \\$$ 
Solution:
​$$\left( \frac{1}{4} \right)^{-4} = 4^4 = 256 \\\left( \frac{1}{2} \right)^{-4} = 2^4 = 16 \\\left( \frac{1}{6} \right)^{-4} = 6^4 = 1296 \\\text{Adding all:} \\256 + 16 + 1296 = \boxed{1568}$$​​