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    The temperature in a city at 6:00 AM was −4∘-4^∘−4∘​ C. During the day, the temperature rose steadily by a certain number of degrees. By 3:00 PM,
    Question

    The temperature in a city at 6:00 AM was 4-4^∘​ C. During the day, the temperature rose steadily by a certain number of degrees. By 3:00 PM, the temperature reached +99^∘​ C. What was the total rise in temperature during that time?

    A.

    13C13^∘ C​​

    B.

    5C5^∘ C​​

    C.

    9C9^∘ C​​

    D.

    15C15^∘ C​​

    Correct option is A

    Given
    Initial temperature at 6:00 AM = 4C-4^\circ C​​
    Final temperature at 3:00 PM = +9C+9^\circ C​​

    Formula Used
    Total Rise in Temperature = Final Temperature - Initial Temperature

    Solution
    Substitute the given values into the formula:
    Total Rise = 9 - (-4)
    Total Rise = 9 + 4 = 13C13^\circ C​​

    Final Answer
    So the correct answer is (a)

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