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The temperature in a city at 6:00 AM was −4∘-4^∘−4∘​ C. During the day, the temperature rose steadily by a certain number of degrees. By 3:00 PM,
Question

The temperature in a city at 6:00 AM was 4-4^∘​ C. During the day, the temperature rose steadily by a certain number of degrees. By 3:00 PM, the temperature reached +99^∘​ C. What was the total rise in temperature during that time?

A.

13C13^∘ C​​

B.

5C5^∘ C​​

C.

9C9^∘ C​​

D.

15C15^∘ C​​

Correct option is A

Given
Initial temperature at 6:00 AM = 4C-4^\circ C​​
Final temperature at 3:00 PM = +9C+9^\circ C​​

Formula Used
Total Rise in Temperature = Final Temperature - Initial Temperature

Solution
Substitute the given values into the formula:
Total Rise = 9 - (-4)
Total Rise = 9 + 4 = 13C13^\circ C​​

Final Answer
So the correct answer is (a)

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