​$$60\%\text{ of }4500-\frac{9^3\times48}{\sqrt{256}}-20\%\text{ of }95=x$$​. Find the value of x ?

Correct option is D

Given:
Equation: $$60\%\text{ of }4500-\frac{9^3\times48}{\sqrt{256}}-20\%\text{ of }95=x$$​​
Solution:
​$$60\%\times4500-\frac{9^3\times48}{\sqrt{256}}-20\%\times95 \\ \ \\= 2700-\frac{9^3\times48}{\sqrt{256}}-20\%\times95\\ \ \\= 2700-\frac{729\times48}{\sqrt{256}}-20\%\times95\\ \ \\= 2700-\frac{34992}{\sqrt{256}}-20\%\times95\\ \ \\= 2700-\frac{34992}{16}-20\%\times95\\ \ \\= 2700-2187-20\%\times95\\ \ \\= 2700-2187-19\\ \ \\= 513-19\\ \ \\= 494$$​​

Thus, 

x = 494