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Find the value of (1−cos⁡2θ)(cot⁡2θ+1)−1(1 - \cos^2 \theta)(\cot^2 \theta + 1) - 1(1−cos2θ)(cot2θ+1)−1 ? ​
Question

Find the value of (1cos2θ)(cot2θ+1)1(1 - \cos^2 \theta)(\cot^2 \theta + 1) - 1 ? ​

A.

sec2θ\sec^2\theta​​

B.

0

C.

2

D.

-2

Correct option is B

Given:
(1cos2θ)(cot2θ+1)1(1 - \cos^2 \theta)(\cot^2 \theta + 1) - 1
Used identity:
cos2θ+sin2θ=1\cos^2 \theta + \sin^2 \theta = 1
Solution:
=(1cos2θ)(cot2θ+1)1 =sin2θ×(cos2θsin2θ+1)1 =sin2θ×(cos2θ+sin2θsin2θ)1 =sin2θ×(1sin2θ)1 =11 =0= (1 - \cos^2 \theta)(\cot^2 \theta + 1) - 1 \\\ \\= \sin^2 \theta \times \left(\frac{\cos^2 \theta}{\sin^2 \theta} + 1\right) - 1 \\ \ \\= \sin^2 \theta \times \left(\frac{\cos^2 \theta + \sin^2 \theta}{\sin^2 \theta}\right) - 1 \\\ \\= \sin^2 \theta \times \left(\frac{1}{\sin^2 \theta}\right) - 1 \\\ \\= 1 - 1 \\\ \\= 0​​​

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