Find the sum of digits of the biggest 6-digit number divisible by 14, 15, 16, 18 and 24.
Given,
The given numbers are 14, 15, 16, 18, and 24.
Concept:
LCM = Least common multiple
Largest 6 digit number is 999999
Solution:
14 = 2 × 7
15 = 3 × 5
16 = 2 × 2 × 2 × 2
18 = 2 × 3 × 3
24 = 2 × 2 × 2 × 3
=> LCM of 14, 15, 16, 18 and 24 = 2 × 2 × 2 × 2 × 3 × 3 × 5 × 7 = 5040
When we divide 999999 by 5040 we get as remainder 2079
=> Required number = 999999 – 2079 = 997920
∴ Sum of digit of 997920 = 9 + 9 + 7 + 9 + 2 + 0 = 36
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