arrow
arrow
arrow
Find the roots of 2x² - 15x + 28.
Question

Find the roots of 2x² - 15x + 28.

A.

Both negative

B.

Both positive

C.

Not real

D.

One positive, other negative

Correct option is B

The given equation is 2x² - 15x + 28 = 0. To find the roots, we will use the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}​​

Here, a = 2, b = -15, and c = 28.

Calculate the discriminant (b² - 4ac).Discriminant = (15)24(2)(28)=225224=1(-15)^2 - 4(2)(28) = 225 - 224 = 1​​

Since the discriminant is positive, the roots are real and distinct.

Apply the quadratic formula x = 15±12×2=15±14 \frac{15 \pm \sqrt{1}}{2 \times 2} = \frac{15 \pm 1}{4}​​

The two roots are: x1=15+14=164=4x_1 = \frac{15 + 1}{4} = \frac{16}{4} = 4​​

x2=1514=144=3.5x_2 = \frac{15 - 1}{4} = \frac{14}{4} = 3.5​​

Thus, both roots are positive.

Hence, the correct answer is B) Both positive.

Free Tests

Free
Must Attempt

CBT-1 Full Mock Test 1

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon100 Marks
  • timerIcon90 Mins
languageIcon English
Free
Must Attempt

RRB NTPC Graduate Level PYP (Held on 5 Jun 2025 S1)

languageIcon English
  • pdpQsnIcon100 Questions
  • pdpsheetsIcon100 Marks
  • timerIcon90 Mins
languageIcon English
Free
Must Attempt

CBT-1 General Awareness Section Test 1

languageIcon English
  • pdpQsnIcon40 Questions
  • pdpsheetsIcon30 Marks
  • timerIcon25 Mins
languageIcon English
test-prime-package

Access ‘RRB JE’ Mock Tests with

  • 60000+ Mocks and Previous Year Papers
  • Unlimited Re-Attempts
  • Personalised Report Card
  • 500% Refund on Final Selection
  • Largest Community
students-icon
354k+ students have already unlocked exclusive benefits with Test Prime!
Our Plans
Monthsup-arrow