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    Find the roots of 2x² - 15x + 28.
    Question

    Find the roots of 2x² - 15x + 28.

    A.

    Both negative

    B.

    Both positive

    C.

    Not real

    D.

    One positive, other negative

    Correct option is B

    The given equation is 2x² - 15x + 28 = 0. To find the roots, we will use the quadratic formula: x=b±b24ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}​​

    Here, a = 2, b = -15, and c = 28.

    Calculate the discriminant (b² - 4ac).Discriminant = (15)24(2)(28)=225224=1(-15)^2 - 4(2)(28) = 225 - 224 = 1​​

    Since the discriminant is positive, the roots are real and distinct.

    Apply the quadratic formula x = 15±12×2=15±14 \frac{15 \pm \sqrt{1}}{2 \times 2} = \frac{15 \pm 1}{4}​​

    The two roots are: x1=15+14=164=4x_1 = \frac{15 + 1}{4} = \frac{16}{4} = 4​​

    x2=1514=144=3.5x_2 = \frac{15 - 1}{4} = \frac{14}{4} = 3.5​​

    Thus, both roots are positive.

    Hence, the correct answer is B) Both positive.

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