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The nature of the roots of the quadratic equation  x2+4x+8=0x^2 + 4x + 8 = 0x2+4x+8=0​ is:
Question

The nature of the roots of the quadratic equation  x2+4x+8=0x^2 + 4x + 8 = 0​ is:

A.

real, irrational, unequal roots

B.

real, rational, unequal roots

C.

real, rational, equal roots

D.

not real roots

Correct option is D

Given:

The quadratic equation is x2+4x+8=0 x^2 + 4x + 8 = 0​​

Concept Used:
The nature of the roots of a quadratic equation ax2+bx+c=0ax^2 + bx + c = 0​ can be determined using the discriminant Δ, given by:

Δ=b24acΔ = b^2 - 4ac​​

If Δ > 0, the equation has two distinct real roots.

If Δ = 0, the equation has exactly one real root (repeated root).

If Δ < 0, the equation has two complex (imaginary) roots.

Solution:
For the equation x2+4x+8=0 x^2 + 4x + 8 = 0​, we have:

a = 1, b = 4, c = 8

Calculate the discriminant:

Δ = 42 − 4(1)(8)

=16 − 32 = −16

Since Δ = −16, which is less than 0.

Thus, the nature of the roots is complex or not real roots(imaginary).

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