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Find the least number which when divided by 8, 12 and 16, leaves three as the remainder in each case but when divided by 7 leaves no remainder.
Question

Find the least number which when divided by 8, 12 and 16, leaves three as the remainder in each case but when divided by 7 leaves no remainder.

A.

266

B.

248

C.

147

D.

149

Correct option is C

Given:

Divisors: 8, 12, 16.

Remainder when divided by 8, 12, and 16: 3.

The number must be divisible by 7.

Solution:

L.C.M. of  8, 12, and 16 is 48.

But, get remainder = 3

Checking multiples of 48 (accounting for the remainder of 3):

51 (48 + 3) is not divisible by 7.

99 (48×2 + 3) is not divisible by 7.

147 (48×3 + 3) is divisible by 7.

∴ The correct answer is 147.

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