Find the HCF of $$\frac{3}{2},\frac{9}{8},\frac{81}{16}$$​, and $$\frac{27}{10}$$​.

Correct option is D

​Given:

The fractions:

​$$\frac{3}{2}, \frac{9}{8}, \frac{81}{16}, \frac{27}{10}$$​​

Formula Used:

HCF of fractions = $$\frac{\text{HCF of numerators}}{\text{LCM of denominators}}$$​​

Solution:

HCF =​$$\frac{\text{HCF of 3, 9, 81, 27}}{\text{LCM of 2, 8, 16, 10}} = \frac{3}{80}$$

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