Find the HCF of  $$\frac{2}{3} , \frac{4}{5} \space and \frac{3}{2}$$ .

Correct option is C

Given: ​

​$$\frac{2}{3} ,\ \frac{4}{5} , \ \frac{3}{2}$$ 

Formula Used: ​

For HCF of fractions = $$\frac{HCF \space of \space the \space numerator}{LCM \space of \space the \space denominator}$$ 

Solution: 

​$$\frac{2}{3} ,\ \frac{4}{5} , \ \frac{3}{2}$$  

HCF of 2, 4, 3 = 1 

LCM of 3, 5, 2 = 30 

So, HCF of ​$$\frac{2}{3} ,\ \frac{4}{5} , \ \frac{3}{2}$$ = $$\frac{1}{30}$$​​