Find the HCF of 2 × 3² × 5², 5 × 3 × 2² and 5² × 3 × 2².
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- 1)
The number of pairs of positive integers whose sum is 99 and HCF is 9 is
- 2)
Find the HCF of 2.8, 11.2 and 0.84 .
- 3)
Find the Highest Common Factor (HCF) of 372, 732 and 2196.
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If the HCF of the expressions (x + 3) (2x² – 3x + a) and (x – 2) (3x² + 10x – b) is x² + x – 6, then what is the value of (2a – 3b) ?
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The greatest number, which divides 1938 and 2337 to leave 0 and 3 respectively as remainders, is:
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The greatest number, which divides 711 and 1040 to leave 48 and 20 respectively as remainders, is:
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The greatest number that divides 210, 1245 and 2160 is:
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There are four equilateral triangles with sides 95 cm, 76 cm, 57 cm and 152 cm. What maximum size scale (in cm) can measure all of them exactly?
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The greatest number, which divides 2340 and 1551 to leave 40 and 33 respectively as remainders, is:
- 10)The greatest number, which divides 1163 and 2214 to leave 15 and 82 respectively as remainders, is:
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Access ‘RRB JE CBT-I’ Mock Tests with
- 60000+ Mocks and Previous Year Papers
- Unlimited Re-Attempts
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- 500% Refund on Final Selection
- Largest Community
Suggested Test Series
Similar Questions
- 1)
The number of pairs of positive integers whose sum is 99 and HCF is 9 is
- 2)
Find the HCF of 2.8, 11.2 and 0.84 .
- 3)
Find the Highest Common Factor (HCF) of 372, 732 and 2196.
- 4)
If the HCF of the expressions (x + 3) (2x² – 3x + a) and (x – 2) (3x² + 10x – b) is x² + x – 6, then what is the value of (2a – 3b) ?
- 5)
The greatest number, which divides 1938 and 2337 to leave 0 and 3 respectively as remainders, is:
- 6)
The greatest number, which divides 711 and 1040 to leave 48 and 20 respectively as remainders, is:
- 7)
The greatest number that divides 210, 1245 and 2160 is:
- 8)
There are four equilateral triangles with sides 95 cm, 76 cm, 57 cm and 152 cm. What maximum size scale (in cm) can measure all of them exactly?
- 9)
The greatest number, which divides 2340 and 1551 to leave 40 and 33 respectively as remainders, is:
- 10)The greatest number, which divides 1163 and 2214 to leave 15 and 82 respectively as remainders, is: