Given:
When dividing 1657, the remainder is 6.
When dividing 2037, the remainder is 5.
Solution:
If a number N leaves a remainder of 6 when dividing 1657, then 1657 − 6 = 1651 is divisible by N.
Similarly, if N leaves a remainder of 5 when dividing 2037, then 2037 − 5 = 2032 is divisible by N.
1651 = 13 × 127
2032 = 4 × 4 × 127
HCF of 1651 and 2032 = 127
Thus, The greatest number N is 127.
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80 Questions
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60 Mins English English20 Questions40 Marks12 Mins English English80 Questions160 Marks60 Mins EnglishFind the Highest Common Factor (HCF) of 372, 732 and 2196.
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