Find the greatest number that divides 128, 303 and 247, leaving remainders 4, 7 and 19, respectively.
Concept Used:
The greatest common Divisor of numbers x, y, and z leaving remainder a, b, and c will be H.C.F. of (x - a), (y - b), and (z- c)
Solution:
x = 128, y = 303, z = 247
a = 4, b = 7, c = 19
Required Number = HCF of [(128 - 4), (303 - 7), (247 - 19)]
= HCF of 124, 296, 228 = 4.
Greatest Number =4
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