Find the average of the squares of the consecutive odd numbers from 1 to 21.

Correct option is C

​$$\text{Given the consecutive odd numbers from 1 to 21:} \\1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21 \\[10pt]\text{To find the average of the squares of these numbers:} \\\text{Average} = \frac{1^2 + 3^2 + 5^2 + 7^2 + 9^2 + 11^2 + 13^2 + 15^2 + 17^2 + 19^2 + 21^2}{11} \\[10pt]= \frac{1 + 9 + 25 + 49 + 81 + 121 + 169 + 225 + 289 + 361 + 441}{11} \\[10pt]= \frac{1771}{11} = 161$$

Correct answer is (c) 161.