Find the average of the first five odd multiples of 9.

Correct option is B

Given:
The first five odd multiples of 9 are 9, 27, 45, 63, and 81.
Formula Used:
Average of n numbers = $$\frac{\text{Sum of all numbers}}{n}$$​​
Solution:
Sum of the first five odd multiples of 9 = 9 + 27 + 45 + 63 + 81 = 225
Average = $$\frac{225}{5}$$​= 45
Thus, the average of the first five odd multiples of 9 is 45.