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    ​Emission maximum of a fluorophore is shifted to longer wavelength compared to the excitation wavelength. What is the reason?​
    Question

    Emission maximum of a fluorophore is shifted to longer wavelength compared to the excitation wavelength. What is the reason?

    A.

    Non-radiative loss of excitation energy

    B.

    Partial absorbance of incident light

    C.

    Scattering of light by molecules

    D.

    Radiative loss of excitation energy

    Correct option is A

    Explanation-

    Option A - Non-radiative loss of excitation energy 
    This phenomenon is known as the Stokes shift. When a fluorophore absorbs light (excitation), some of the absorbed energy is lost through non-radiative processes (like vibrational relaxation) before the molecule emits light (emission). As a result, the emitted light has less energy and therefore a longer wavelength than the absorbed (excitation) light.

    Incorrect options-
    Option B - Partial absorbance of incident light
    Partial absorbance refers to how much of the incoming light is absorbed, but it does not explain the shift in wavelength between excitation and emission. It affects intensity, not wavelength.
    Option C - Scattering of light by molecules 
    Scattering affects the direction and possibly the intensity of light but not the wavelength difference between excitation and emission.
    Option D - Radiative loss of excitation energy 
    Radiative processes involve emission of photons (light), not energy loss. The energy lost before emission (causing the red-shift) is non-radiative, not radiative.

    So, the correct answer is Option A -Non-radiative loss of excitation energy
    This is the correct explanation for the Stokes shift, where some energy is lost through non-radiative processes before emission, causing a longer emission wavelength.


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