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    Consider the two statements given below S 1: When percentage errors Δm/m in the measurement of mass and speed of an object are 2 and 1 respectively
    Question

    Consider the two statements given below
    S 1: When percentage errors Δm/m in the measurement of mass and speed of an object are 2 and 1 respectively, the percentage error in the measurement of the kinetic energy of the object is 4%.
    S 2: The kinetic energy of the object is given by mass × speed.

    A.

    S 1 is correct but S 2 is not correct.

    B.

    S 1 is not correct while S 2 is correct.

    C.

    Both S 1 and S 2 are correct and S 2 is the correct explanation of S 1.

    D.

    Both S 1 and S 2 are correct but S 2 is not the correct explanation of S 1.​

    Correct option is C


    Correct answer is C
    Calculation:
    Kinetic energy (KE) is given by KE = 1/2 × m × v2, where m is the mass and v is the speed.
    The percentage error in KE can be calculated using the formula for error propagation:
    (% error in KE) = (% error in m) + 2 × (% error in v).
    Substituting the given values:
    (% error in KE) = 2% + 2 × 1% ⇒ 2% + 2% = 4%.
    Thus, S 1 is correct because the percentage error in KE is indeed 4%.
    S 2 is correct as it accurately defines the formula for kinetic energy.
    Since S 2 explains the formula used in the calculation of S1, it is the correct explanation of S 1.

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