Consider a coil of 150 turns carrying a current of 10 A. If an induced electromotive force of 300 V is produced when this current is reversed in 0.01 second, then calculate the flux linked with the coil

Correct option is C

Given: 

​$$e = 300 \, \text{V} \\I = 10 \, \text{A} \\\text{Current reverse in } 0.01 \, \text{sec.}$$

$$\frac{di}{dt} = \frac{10 - (-10)}{0.01} = \frac{20}{0.01}$$

$$300 = L \cdot \frac{20}{0.01}$$

$$L = 0.15 \, \text{H}$$

$$0.15 = \frac{150 \cdot \phi}{10}$$

$$\phi = 0.01 \, \text{Wb}$$​​​​​​​