Compute the value of  $$\frac{[ (0.35)^2 - (0.02)^2]}{0.19}$$  up to 3 decimal places:

Correct option is B

Given: 

$$\frac{[ (0.35)^2 - (0.02)^2]}{0.19}$$​​

Formula used:
​$$a^2 - b^2 = (a+b)(a-b)$$​​
Calculation:
​$$= \frac{(0.35+0.02)(0.35−0.02)}{0.19​} \\ \ \\= \frac{(0.37)(0.33)}{0.19} \ = 0.642$$​​