Among five people named A, B, C, D and E, each has a certain age. C is twice the age of A. A is three times the age of D. D is one fifth the age of B. The age of B is 45. If E is equal the age of C, what is the age of E?
Given:
C is twice the age of A.
A is three times the age of D.
D is one fifth the age of B.
The age of B is 45.
E is equal to the age of C.
Solution:
From the given, b = 45, so:
d = = 9
a = 3d
a = 3 × 9 = 27
c = 2a:
c = 2 × 27 = 54
Since e = c, the age of E is:
e = 54
Thus, the age of E is 54 years.
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