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    AB is the diameter of a circle with centre O. P be a point on it. If ∠AOP=95∘, then ∠OBP=
    Question

    AB is the diameter of a circle with centre O. P be a point on it. If ∠AOP=95∘, then ∠OBP=

    A.

    57.5°

    B.

    45.5°

    C.

    47.5°

    D.

    55.5°

    Correct option is C

    Given:
    AB is the diameter of the circle with center O. ∠AOP = 95°.
    Formula Used:
    Since ∠AOP is an angle subtended by the diameter, the angle at the circumference subtended by the same arc is half of ∠AOP.
    Solution:

    Since AB is the diameter, ∠AOP = 95°

    triangle OBP is a  s implies ∠OBP =952\frac{95}{2}  ( Because  ∠OBP  is the exterior angle of triangle OPB and OP = OB both are the radius of this circle so ∠OPB = ∠OBP)
     ∠OPB+ ∠OBP  = 95°

    ∠OBP =(95°)2=47.5°\frac{ (95°)}2 = 47.5°​​
    ∠OBP = 47.5°

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