AB is the diameter of a circle with centre O. P be a point on it. If ∠AOP=95∘, then ∠OBP=

Correct option is C

Given:
AB is the diameter of the circle with center O. ∠AOP = 95°.
Formula Used:
Since ∠AOP is an angle subtended by the diameter, the angle at the circumference subtended by the same arc is half of ∠AOP.
Solution:

Since AB is the diameter, ∠AOP = 95°

triangle OBP is a  s implies ∠OBP =$$\frac{95}{2}$$  ( Because  ∠OBP  is the exterior angle of triangle OPB and OP = OB both are the radius of this circle so ∠OPB = ∠OBP)
 ∠OPB+ ∠OBP  = 95°

∠OBP =$$\frac{ (95°)}2 = 47.5°$$​​
∠OBP = 47.5°