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A vessel contains 80 liters of a mixture of milk and water in the ratio of 11:5, respectively. If 32 liters of mixture are taken out, then how much qu
Question


A vessel contains 80 liters of a mixture of milk and water in the ratio of 11:5, respectively. If 32 liters of mixture are taken out, then how much quantity of milk should be added to the mixture such that the ratio of milk to water becomes 8:3, respectively?

A.

10

B.

9

C.

7

D.

4

E.

6

Correct option is C


Information Given:
Total mixture in the vessel = 80 liters
Ratio of milk to water in the mixture = 11:5
32 liters of the mixture is taken out.
Formulas Used:
Milk=Total mixture×Milk ratioTotal ratio\text{Milk} = \frac{\text{Total mixture} \times \text{Milk ratio}}{\text{Total ratio}}
Water=Total mixture×Water ratioTotal ratio\text{Water} = \frac{\text{Total mixture} \times \text{Water ratio}}{\text{Total ratio}}
New ratio of milk to water=New quantity of milkNew quantity of water\text{New ratio of milk to water} = \frac{\text{New quantity of milk}}{\text{New quantity of water}}
Basic Explanation:
Quantity of milk = 80×11/16=55 litres
Quantity of water = 80-55=25 litres
Let quantity of milk added be x liters
ATQ,
3(33+x)=8(15)
33+x=40
x=7

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