A train travelling at a speed of 69 km/h passes an electric pole in 8 seconds and a platform in 32 seconds. What is the length of the platform?

Correct option is A

Given:

Speed of the train = 69 km/h

Time taken to pass an electric pole = 8 seconds

Time taken to pass a platform = 32 seconds

Formula Used:

Distance = Speed × Time

Solution:

Distance covered when passing the electric pole = Speed × Time = $$69 \times \frac{5}{18} \, \text{m/s} \times 8 \, \text{s}$$​ = 153.34 m

Therefore, the length of the train = 153.34 meters.

Distance covered when passing the platform = Speed × Time = $$69 \times \frac{5}{18} \, \text{m/s}$$ ×32 s = 613.34 m

The total distance covered when passing the platform is the sum of the length of the train and the length of the platform.

Length of the platform = Total distance − Length of the train

Length of the platform=613.34 m−153.34 m = 460 m

Thus, the length of the platform is approximately 460 meters.

Alternate Method:

Length of platform = $$69 \times \frac{5}{18}$$ $$\times (32-8)$$

= $$69 \times \frac{5}{18} \times 24$$ = 460 m